4x^2+4y^2=128

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Solution for 4x^2+4y^2=128 equation:


Simplifying
4x2 + 4y2 = 128

Solving
4x2 + 4y2 = 128

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-4y2' to each side of the equation.
4x2 + 4y2 + -4y2 = 128 + -4y2

Combine like terms: 4y2 + -4y2 = 0
4x2 + 0 = 128 + -4y2
4x2 = 128 + -4y2

Divide each side by '4'.
x2 = 32 + -1y2

Simplifying
x2 = 32 + -1y2

Reorder the terms:
-32 + x2 + y2 = 32 + -1y2 + -32 + y2

Reorder the terms:
-32 + x2 + y2 = 32 + -32 + -1y2 + y2

Combine like terms: 32 + -32 = 0
-32 + x2 + y2 = 0 + -1y2 + y2
-32 + x2 + y2 = -1y2 + y2

Combine like terms: -1y2 + y2 = 0
-32 + x2 + y2 = 0

The solution to this equation could not be determined.

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